answer:Since p(x) is a monic cubic polynomial, we can write it in the form p(x) = (x-r_1)(x-r_2)(x-r_3), where r_1, r_2, and r_3 are the roots of the polynomial. We know that p(3-2i) = 0, so one of the roots must be 3-2i. Since the coefficients of p(x) are real, the complex conjugate 3+2i must also be a root. We also know that p(0) = -52. Plugging in x=0 into our polynomial, we get p(0) = (0-r_1)(0-r_2)(0-r_3) = -52. Since we already have two of the roots, we can write this as (0-(3-2i))(0-(3+2i))(0-r_3) = -52. Expanding this equation, we get (3-2i)(3+2i)(0-r_3) = -52. Simplifying, we get 13(0-r_3) = -52, or r_3 = 4. Therefore, the polynomial p(x) is (x-(3-2i))(x-(3+2i))(x-4). Expanding this, we get p(x) = (x^2-6x+13)(x-4). Thus, p(x) in expanded form is boxed{x^3 - 10x^2 + 37x - 52}.The answer is: x^3-10x^2+37x-52

answer:We substitute the given values of x and y into the expression 2times x - 3 times y. We get 2times 2 - 3 times 1 = 4 - 3 = boxed{1}. The answer is: 1

answer:Each batch contains 48 baguettes, so three batches contain a total of 48 x 3 = 144 baguettes. From the first batch, 37 baguettes were sold, so there are 144 - 37 = 107 baguettes remaining. From the second batch, 52 baguettes were sold, so there are 107 - 52 = 55 baguettes remaining. From the third batch, 49 baguettes were sold, so there are 55 - 49 = 6 baguettes remaining. Therefore, there are 6 baguettes remaining. 6 The answer is: 6

answer:To find the fraction that is halfway between frac{2}{3} and frac{4}{5}, we can take the average of the two fractions. The average is frac{frac{2}{3} + frac{4}{5}}{2} = frac{frac{10}{15} + frac{12}{15}}{2} = frac{frac{22}{15}}{2} = frac{22}{15} div 2 = frac{22}{15} cdot frac{1}{2} = boxed{frac{11}{15}}. The answer is: frac{11}{15}