Skip to content
🤔prompts chat🧠
🔍
question:Phil has X green marbles and 3 purple marbles in a bag. He removes a marble at random, records the color, puts it back, and then repeats this process until he has withdrawn 6 marbles. What is the probability that exactly three of the marbles that he removes are green? Express your answer as a decimal rounded to the nearest thousandth. If we know the answer to the above question is 0.185, what is the value of unknown variable X?

answer:We want to find the value of X in the given situation. We are told that Phil has X green marbles and 3 purple marbles in a bag. He removes a marble at random, records the color, puts it back, and repeats this process until he has withdrawn 6 marbles. To find the probability that exactly three of the marbles he removes are green, we can use the concept of combinations. The total number of marbles in the bag is X + 3. The total number of ways to choose 6 marbles from X + 3 marbles is given by the combination formula: C(n, r) = frac{n!}{r!(n-r)!} In this case, n is X + 3 (total number of marbles) and r is 6 (number of marbles Phil removes). The number of ways to choose exactly 3 green marbles from X green marbles is given by the combination formula: C(X, 3) = frac{X!}{3!(X-3)!} The probability of choosing exactly 3 green marbles out of 6 marbles is the ratio of the number of ways to choose 3 green marbles to the total number of ways to choose 6 marbles: Probability = frac{C(X, 3)}{C(X+3, 6)} Given that the probability is 0.185, we can set up the equation: 0.185 = frac{C(X, 3)}{C(X+3, 6)} To solve for X, we can try different values and calculate the probability. Let's start with X = 5: 0.185 = frac{C(5, 3)}{C(8, 6)} 0.185 = frac{10}{28} The equation does not hold true for X = 5. Let's try X = 6: 0.185 = frac{C(6, 3)}{C(9, 6)} 0.185 = frac{20}{84} The equation does not hold true for X = 6. Let's try X = 7: 0.185 = frac{C(7, 3)}{C(10, 6)} 0.185 = frac{35}{210} The equation holds true for X = 7. Therefore, the value of X is 7. The answer is: 7

question:Georgie is a varsity player on a football team. He can run 40 yards within x seconds. If he can improve his speed by forty percent, how many yards will he be able to run within 10 seconds? If we know the answer to the above question is 112, what is the value of unknown variable x?

answer:Georgie can run 40 yards within x seconds. If he improves his speed by forty percent, he will be able to run 40 + 40% of 40 = 40 + (40/100)*40 = 40 + 16 = 56 yards within x seconds. We are given that Georgie will be able to run 112 yards within 10 seconds, so we can write: 56/x = 112/10. Cross-multiplying, we get: 56*10 = 112*x. Simplifying, we get: 560 = 112*x. Dividing both sides by 112, we get: x = 5. The value of x is 5. 5 The answer is: 5

question:The total number of lions in a park is twice the number of leopards in the same park. The number of elephants is half the combined number of lions and leopards. Calculate the total population of the three animals in the park if the number of lions is 200.

answer:If the number of lions is 200, then the number of leopards is 200/2 = 100. The combined number of lions and leopards is 200 + 100 = 300. The number of elephants is half the combined number of lions and leopards, so it is 300/2 = 150. The total population of the three animals in the park is 200 + 100 + 150 = 450. 450 The answer is: 450

question:f Jon's laundry machine can handle 5 pounds of laundry at a time, and 4 shirts weigh 1 pound while 2 pairs of pants also weigh 1 pound, how many loads of laundry does Jon need to do if he has 20 shirts and 20 pants to wash?

answer:If 4 shirts weigh 1 pound, then 1 shirt weighs 1/4 = 0.25 pounds. Similarly, if 2 pairs of pants weigh 1 pound, then 1 pair of pants weighs 1/2 = 0.5 pounds. Jon has 20 shirts, so they weigh 20 * 0.25 = 5 pounds. Jon also has 20 pairs of pants, so they weigh 20 * 0.5 = 10 pounds. In total, Jon needs to wash 5 + 10 = 15 pounds of laundry. Since Jon's laundry machine can handle 5 pounds of laundry at a time, he needs to do 15 / 5 = 3 loads of laundry. 3 The answer is: 3

Released under the Diffusion License.

has loaded