answer:Sasha made x chocolate muffins. Melissa made 4 times as many muffins as Sasha, which means Melissa made 4x muffins. The total number of muffins made by Sasha and Melissa is x + 4x = 5x. Tiffany made half of Sasha and Melissa's total number of muffins, which means Tiffany made (1/2) * 5x = 2.5x muffins. The total number of muffins contributed to the fundraiser is the sum of the muffins made by Sasha, Melissa, and Tiffany: x + 4x + 2.5x = 7.5x. We are given that the total amount of money contributed is 900, so we can write: 7.5x * 4 = 900. Dividing both sides by 4, we get: 7.5x = 225. Dividing both sides by 7.5, we get: x = 30. The value of x is 30. 30 The answer is: 30

answer:Jeff currently has 3 cabinets over one counter in his kitchen. He decides to install twice as many cabinets over 3 different counters each, so he installs 2*3 = 6 cabinets over each counter. He installs 6 cabinets over each of the 3 counters, so he installs a total of 6*3 = 18 cabinets over the counters. He also decides to install an additional 5 cabinets. Therefore, the total number of cabinets he will have in his kitchen is 3 + 18 + 5 = 26 cabinets. 26 The answer is: 26

answer:To solve this problem, we need to determine the value of x, which represents the number of students in the class. Let's break down the information given: Number of mini-cupcakes: 14 Number of donut holes: 12 Number of desserts per student: 2 We can set up the equation as follows: Number of mini-cupcakes + Number of donut holes = Number of desserts per student * Number of students 14 + 12 = 2 * x Let's simplify and solve for x: 26 = 2x To isolate x, we divide both sides of the equation by 2: 26 / 2 = 2x / 2 13 = x The value of x is 13. 13 The answer is: 13

answer:The formula for the nth term of an arithmetic sequence is given by a_n = a_1 + (n-1)d, where a_1 is the first term, n is the term number, and d is the common difference. In this case, we are given that a_1 = 2, a_{20} = 59, and n = 5. We can use this information to find the common difference d. Using the formula a_{20} = a_1 + (20-1)d, we have 59 = 2 + 19d, which gives d = 3. Now we can find the 5th term a_5 using the formula a_5 = a_1 + (5-1)d. Plugging in the values, we have a_5 = 2 + (5-1)(3) = 2 + 4(3) = 2 + 12 = boxed{14}. The answer is: 14