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question:What is the value of the ceiling function applied to the square root of 2, plus the ceiling function applied to the square root of 22, plus the ceiling function applied to the square root of 222?
answer:The ceiling function rounds up to the nearest whole number. We have lceil sqrt{2} rceil = 2, lceil sqrt{22} rceil = 5, and lceil sqrt{222} rceil = 15. So the sum is 2+5+15 = boxed{22}. The answer is: 22
question:Mark wants to build a pyramid of soda cases that's four levels tall. Each level of the pyramid has a square base where each side is one case longer than the level above it. The top level is just one case. How many cases of soda does Mark need?
answer:The top level of the pyramid has just one case. The second level has a base of 2x2 cases, so it needs 2x2 = 4 cases. The third level has a base of 3x3 cases, so it needs 3x3 = 9 cases. The fourth level has a base of 4x4 cases, so it needs 4x4 = 16 cases. To find the total number of cases needed, we add up the number of cases for each level: 1 + 4 + 9 + 16 = 30 Mark needs 30 cases of soda to build the pyramid. 30 The answer is: 30
question:The arithmetic mean of 12 scores is 82. When the highest and lowest scores are removed, the new mean becomes 84. If the highest of the 12 scores is 98, what is the lowest score?
answer:The sum of the 12 scores is 12 times 82 = 984. The sum of the remaining 10 scores is 10 times 84 = 840. The difference between the sum of all 12 scores and the sum of the remaining 10 scores is 984 - 840 = 144. This difference is equal to the sum of the highest and lowest scores, so the lowest score is 144 - 98 = boxed{46}. The answer is: 46
question:f the area of a circle is smaller than 60pi square inches, what is the largest possible integer value in inches for the radius of the circle?
answer:The area of a circle is given by the formula A=pi r^2, where r is the radius of the circle. We are given that the area is smaller than 60pi, so we have the inequality pi r^2 < 60pi. Dividing both sides of the inequality by pi, we get r^2 < 60. Taking the square root of both sides, we get r < sqrt{60}. Since we are looking for the largest possible integer value for the radius, we take the floor function of sqrt{60}, which is boxed{7}. The answer is: 7