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question:The equation y = 3 intersects the graph y = 4x^2 + x - 1 at points A and B. The distance between A and B can be expressed as frac{sqrt{m}}{n}, where m and n are positive integers that are relatively prime. Find the value of m - n.
answer:4x^2 + x - 1 = 3 for the x-coordinates of the points of intersection. First, we move all terms to one side to get 4x^2 + x - 4 = 0. Next, we can factor this quadratic as (4x - 1)(x + 4) = 0. Setting each factor equal to zero, we have 4x - 1 = 0 and x + 4 = 0. Solving these equations, we find x = frac{1}{4} and x = -4. So, the points of intersection are left(frac{1}{4}, 3right) and (-4, 3). The distance between these points is sqrt{left(frac{1}{4} - (-4)right)^2 + (3 - 3)^2} = sqrt{frac{65}{16}} = frac{sqrt{65}}{4}. Therefore, m - n = 65 - 4 = boxed{61}.The answer is: 61
question:Out of the x marbles that Cindy had, she gave her four friends 80 marbles each. What's four times the number of marbles she has remaining? If we know the answer to the above question is 720, what is the value of unknown variable x?
answer:Cindy gave her four friends 80 marbles each, so she gave away a total of 4 * 80 = 320 marbles. The number of marbles she has remaining is x - 320. We are given that four times the number of marbles she has remaining is 720, so we can write: 4 * (x - 320) = 720. Simplifying the left side, we get: 4x - 1280 = 720. Adding 1280 to both sides, we get: 4x = 2000. Dividing both sides by 4, we get: x = 500. The value of x is 500. 500 The answer is: 500
question:What is the smallest possible value of x such that 2x^2+24x-60=x(x+13)?
answer:We begin by expanding the right side of the equation to get x^2+13x. Next, we subtract x^2+13x from both sides to get 2x^2+24x-60-x^2-13x=0. Simplifying, we have x^2+11x-60=0. Factoring the quadratic, we get (x+15)(x-4)=0. Setting each factor equal to zero, we have x+15=0 or x-4=0. Solving each equation, we find x=-15 or x=4. The smallest possible value of x is boxed{-15}. The answer is: -15
question:f Machine A can cap 12 bottles in 1 minute, Machine B can cap 2 fewer bottles than Machine A, and Machine C can cap 5 more bottles than Machine B, how many bottles can these three machines cap in a span of 10 minutes?
answer:Machine A can cap 12 bottles in 1 minute, so in 10 minutes it can cap 12 x 10 = 120 bottles. Machine B can cap 2 fewer bottles than Machine A, so it can cap 12 - 2 = 10 bottles in 1 minute. In 10 minutes, Machine B can cap 10 x 10 = 100 bottles. Machine C can cap 5 more bottles than Machine B, so it can cap 10 + 5 = 15 bottles in 1 minute. In 10 minutes, Machine C can cap 15 x 10 = 150 bottles. Together, these three machines can cap 120 + 100 + 150 = 370 bottles in 10 minutes. 370 The answer is: 370